Show that
\[\arg\max_{ {\bf x}: ||{\bf x}||=1} {\bf x}^T A {\bf x} = {\bf v}_1\]and that
\[\arg\min_{ {\bf x}: ||{\bf x}||=1} {\bf x}^T A {\bf x} = {\bf v}_n\]Why do we only consider unit vectors in the above max/minimization?
$$\arg\min_{\mathcal L} || {\bf x}_i - {\bf x}_i^{\mathcal L} ||^2.$$
Generalize the above for \(k-\)dimensional linear spaces that best represent the rows of \(X\) in a mean square sense.
Write the analogs of the above observations for the columns of \(X\).
If \(A\) is a symmetric matrix, prove the Cayley Hamilton Theorem: \(A\) satisfies its own characteristic equation. Specifically, let \(p(\lambda) = | A- \lambda I |\) be the characteristic equation of \(A\). Show that \(p(A)={\bf 0}\).
For example, the characteristic of \(A=\begin{bmatrix} 1 & 2 \\ 2 & 1 \end{bmatrix}\) is \(\lambda^2 - 2\lambda -3\), and sure enough, \(A^2= AA = \begin{bmatrix} 5 & 4\\4& 5\end{bmatrix}\), so that \(A^2 - 2A -3I =0\). You should of course prove it in general for all symmetric matrices, not a specific example.
The Cayley-Hamilton Theorem holds for all square matrices, not just symmetric matrices. The general proof is too involved for our course. But the symmetric case is easy to prove using the spectral decomposition theorem and elementary observations.